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JEE Advanced Chemistry p Block Elements (Group 15, 16, 17 & 18) 2022 JEE Advanced 2022 (Paper 2)

JEE Advanced Chemistry Question (2022) — Solution

Question

The reaction of Pb NO 3 2  and NaCl in water produces a precipitate that dissolves upon the addition of HCl of appropriate concentration. The dissolution of the precipitate is due to the formation of

Options

  1. A. PbCl 2
  2. B. PbCl 4
  3. C. PbCl 4 2 -
  4. D. PbCl 6 2 -

Answer

C. PbCl 4 2 -

Step-by-step solution

Pb 2 + on reaction with Cl - , produces white precipitate of PbCl 2 Pb 2 + + 2 Cl - ⟶ PbCl 2 ↓ This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate II  ion PbCl 2 ↓ + 2 Cl - ⟶ PbCl 4 2 - On addition of potassium chromate (K2CrO4 ) solution to lead chloride a yellow precipitate of lead chromate is obtained. 

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Related: Chemistry — p Block Elements (Group 15, 16, 17 & 18) · All PYQ Banks