Question
Choose the correct statement(s) among the following.
JEE Advanced
Chemistry
Redox Reactions
2020
JEE Advanced 2020 (Paper 2)
JEE Advanced Chemistry Question (2020) — Solution
Options
- A. SnCl 2 · 2 H 2 O is a reducing agent.
- B. SnO 2 reacts with KOH to form K 2 Sn ( OH ) 6
- C. A solution of PbCl 2 in HCl contains Pb 2 + and Cl - ions.
- D. The reaction of Pb 3 O 4 with hot dilute nitric acid to give PbO 2 is a redox reaction.
Answer
B. SnO 2 reacts with KOH to form K 2 Sn ( OH ) 6
Step-by-step solution
(A) Sn 2 + is a good reducing agent which gets oxidise into Sn 4 + (B) Amphoteric nature. (C) PbCl 2 + 2 Cl - ⟶ PbCl 4 2 - (D) Pb 3 O 4 ( 2 PbO   +   PbO 2 ) + 4 HNO 3 ( Conc . ) → PbO 2 ↓ + 2 Pb NO 3 2 + 6 H 2 O
Related: Chemistry — Redox Reactions · All PYQ Banks