Question
H 2   S ( 5 moles) reacts completely with acidified aqueous potassium permanganate solution. In this reaction, the number of moles of water produced is x , and the number of moles of electrons involved is y . The value of ( x + y ) is
JEE Advanced
Chemistry
Redox Reactions
2023
JEE Advanced 2023 (Paper 2)
JEE Advanced Chemistry Question (2023) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
KMnO 4 ⟶ H + Mn 2 + S - 2 ⟶   S 0 The number of electrons involved per molecule is called n-factor. n-factor of KMnO 4 = 5 n-factor of S - 2 H 2   S = 2 Moles × n - factor   =   number   of   equivalents n KMnO 4 × 5 = ( 5 × 2 ) H 2   S ∴ n KMnO 4 = 2 ∴ 2 KMnO 4 + 3 H 2 SO 4 + 5 H 2   S → K 2 SO 4 + 2 MnSO 4 + 5   S + 8 H 2 O Number of moles of water produced =   8   Number of moles of electrons involved = 10 ∴    x = 8 , y = 10 ⇒ ( x + y ) = 18
Related: Chemistry — Redox Reactions · All PYQ Banks