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JEE Advanced Chemistry Solid State 2021 JEE Advanced 2021 (Paper 1)

JEE Advanced Chemistry Question (2021) — Solution

Question

For the given close packed structure of a salt made of cation X and anion Y shown below (ions of only one face are shown for clarity), the packing fraction is approximately (packing fraction  = packing   efficiency 100 )

Options

  1. A. 0 . 74
  2. B. 0 . 63
  3. C. 0 . 52
  4. D. 0 . 48

Answer

B. 0 . 63

Step-by-step solution

Total number of atoms in a unit cell No. of  x   = 6 × 1 2 = 3  atom (at face centres) No. of  y   = 8 × 1 8 = 1  atom (at all corners) So, the formula of compound is  x 3 y Now If radius of  x  is  r  and radius of  y  is  R  then side length  a = 2 R and face diagonal  2 a = 2 R + 2 r r = 2 − 1 R Now Packing fraction  = volume   of   atoms   Volume   of   unit   cell = 1 × 4 3 πR 3 + 3 × 4 3 πr 3 a 3 Substituting a = 2   R and  r = 0 . 414   R = 4 3 πR 3 1 + 3 0 . 414 3 2 R 3 = 4 π 3 × 8   1 + 0 . 07096 × 3 = π 6 × 1 . 212 = 0 . 63

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