Quantrex Academy · Free JEE Advanced PYQ solutions
JEE Advanced Chemistry Solutions 2025 JEE Advanced 2025 (Paper 2)

JEE Advanced Chemistry Question (2025) — Solution

Question

At 300 K , an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height ( h ) of the solution (density =1.00 ~g ~cm ^ -3 ) where h is equal to 2.00 cm . If the concentration of the dilute solution of the macromolecule is 2.00 ~g dm ^ -3 , the molar mass of the macromolecule is calculated to be X 10^4 ~g ~mol ^ -1 . The value of X is . Use : Universal gas constant ( R )=8.3 ~J ~K ^ -1 ~mol ^ -1 and acceleration due to gravity ( g )=10 ~m ~s ^ -2

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

aligned & = g h=10^3 10 2 10^ -2 Pascal =200 Pascal \\ & =C R T \\ & 200= 2 M 1000 8.3 300 \\ & M=24900=2.49 10^4 ~g / mol \\ & X=2.49 aligned

Practice more on Quantrex App →

Related: Chemistry — Solutions · All PYQ Banks