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JEE Advanced Chemistry Some Basic Concepts of Chemistry 2021 JEE Advanced 2021 (Paper 1)

JEE Advanced Chemistry Question (2021) — Solution

Question

For the following reaction scheme, percentage yields are given along the arrow: x g and y g are mass of R and U , respectively. (Use: Molar mass (in g mol ^ -1 ) of H , C and O as 1,12 and 16 , respectively) The value of  y is ___.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Mg 2 C 3 → H 2 O Mg ( OH ) 2 + C 3 H 4 ( P ) Propyne   ( 4 g ) CH 3 − C ≡ CH → 33 K ( 100 % ) Hg 2 + CH 3 − C | | O − CH 3 ( S ) Now, one moe of propyne give one mole of acetone.  100 % . one mole of acetone give  0 . 5  moles of  α , β -unsaturated compound  100 %   yield . But given that  80 %  yield. No. of moles of  α , β -unsaturated compound  = 0 .04   mol .  = 0 .04   mol  of  T  can give  = 0 .04   mol  of  U   100 %   yield . But given that  80 %  yield. No. of moles of  U  formed  = 0 . 032 mass of  U  formed  0.032 × 100 = 3 . 20

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