To form a complete monolayer of acetic acid on 1 ~g of charcoal, 100 ~mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P 10^ -23 ~m ^2 surface are

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To form a complete monolayer of acetic acid on 1 ~g of charcoal, 100 ~mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P 10^ -23 ~m ^2 surface area on charcoal, the value of P is _______ [Use given data: Surface area of charcoal =1.5 10^2 ~m ^2 ~g ^ -1 ; Avogadro's number ( N _ A )=6.0 10^ 23 . mol ^ -1 ]

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Correct answer: A. A

aligned & Millimole of acid taken =100 0.5=50 \ & Millimole of NaOH used =40 1=40 \ & Millimole of acid adsorbed =50-40=10 \ & Molecules of acid adsorbed =10 10^ -3 6 10^ 23 =6 10^ 21 \ & Surface area occupied per molecule = 1.5 10^2 6 10^ 21 =0.25 10^ -19 =2500 10^ -23 aligned

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