Molar volume (V_m ) of a van der Waals gas can be calculated by expressing the van der Waals equation as a cubic equation with V_m as the variable. The ratio (in mol dm ^ -3 ) of the coefficient of V_m^2 to the coefficient of V_m for a gas having van der Waals constants a=6.0 dm ^6 ~atm ~mol ^ -2 an

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Molar volume (V_m ) of a van der Waals gas can be calculated by expressing the van der Waals equation as a cubic equation with V_m as the variable. The ratio (in mol dm ^ -3 ) of the coefficient of V_m^2 to the coefficient of V_m for a gas having van der Waals constants a=6.0 dm ^6 ~atm ~mol ^ -2 and b=0.060 dm ^3 ~mol ^ -1 at 300 K and 300 atm is _____ . Use: Universal gas constant (R)=0.082 dm ^3 ~atm ~mol ^ -1 ~K ^ -1

Quantrex Academy · Accepted Answer

Correct answer: A. A

aligned & (P+ a V_m^2 ) (V_m-b )=R T \ & P V_m-b P+ a V_m - a b V_m^2 -R T=0 \ & P V_m^2-(b P+R T) V_m^2+a V_m-a b=0 aligned Coefficient of V _ m ^2=-( bP + RT ) Coefficient of V _ m = a Ratio =- ( bP + RT ) a =- [ 0.06 300+24.6 6 ]=-7.1 .

JEE Advanced Chemistry Question (2025) — Solution

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