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JEE Advanced Chemistry Structure of Atom 2019 JEE Advanced 2019 (Paper 2)

JEE Advanced Chemistry Question (2019) — Solution

Question

The ground state energy of hydrogen atom is - 13.6   e V . Consider an electronic state Ψ of H e + whose energy, azimuthal quantum number and magnetic quantum number are - 3.4   e V ,   2 and 0 respectively. Which of the following statement(s) is(are) true for the state Ψ ?

Options

  1. A. It has 2 angular nodes
  2. B. It has 3 radial nodes
  3. C. It is a 4 d state
  4. D. The nuclear charge experienced by the electron in this state is less than 2 e , where e is the magnitude of the electronic charge.

Answer

C. It is a 4 d state

Step-by-step solution

∵ E H e + = - 13.6 z 2 n 2 = - 13.6 2 2 n 2 = - 3.4 n 2 = 16 ∴ n = 4 n = 4 , l = 2 , m = 0 belongs to 4 d y z orbital → Radial nodes ⇒ n - l - 1 → Angular nodes ⇒ 4 - 2 - 1 = 1 → Angular nodes ⇒ l ⇒ 2 Since H e + is a single e - ion, its nuclear charge experienced.

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