List-I contains various physical/chemical processes, and List-II contains combinations of changes in enthalpy ( H) and entropy ( S). Match each entry in List-I to the appropriate entry in List-II, and choose the correct option. List-I List-II (P) Physisorption (1) H > 0 and S > 0 (Q) Diamond Graphite (2) H (R) Denaturation of protein (3) H (S) Propene Cyclopropane (4) H > 0 and S (5) H 0
C. P 2; Q 5; R 1; S 4
(P) Physisorption is an exothermic process because attractive forces are formed between the adsorbate and the adsorbent, so H (Q) Diamond Graphite is an exothermic process because graphite is the thermodynamically more stable allotrope of carbon at standard conditions ( H 0). This matches (5). (R) Denaturation of protein involves the breaking of hydrogen bonds and the unfolding of its specific 3D structure into a more random coil. Breaking these interactions requires energy ( H > 0) and the unfolding increases randomness ( S > 0). This matches (1). (S) Propene Cyclopropane is an endothermic process because cyclopropane has significant ring strain compared to the open-chain propene, making it less stable ( H > 0). The formation of a rigid ring restricts the degrees of freedom (such as rotation around single bonds), decreasing entropy ( S Thus, P 2, Q 5, R 1, S 4. Answer: P 2; Q 5; R 1; S 4
Related: Chemistry — Thermodynamics (C) · All PYQ Banks