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JEE Advanced Mathematics Application of Derivatives 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Mathematics Question (2021) — Solution

Question

Let f_ 1 :(0, ) R and f_ 2 :(0, ) R be defined by f_ 1 (x)= _ 0 ^ x _ j=1 ^ 21 (t-j)^ j d t, x>0 and f_ 2 (x)=98(x-1)^ 50 -600(x-1)^ 49 +2450, x>0 where, for any positive integer n and real numbers a_ 1 , a_ 2 , , a_ n , _ i=1 ^ n a_ i denotes the product of a_ 1 , a_ 2 , , a_ n . Let m_ i and n_ i , respectively, denote the number of points of local minima and the number of points of local maxima of function f_ i , i=1,2, in the interval (0, ). The value of  2 m 1 + 3 n 1 + m 1 n 1  is _____.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given f 1 x = ∫ 0 x t − 1 t − 2 2 ...... t − 2 t 21 d t ⇒       f ' 1 x = x − 1 x − 2 2 ..... x − 21 21 Checking critical points At all odd integers from  1  to  21   f x  will have an extrema with  1 , 5 , 9 , 13 , 17 , 21  being points of minima &  3 , 7 , 11 , 15 , 19  being points of maxima. So  m 1 = 6  &  n 1 = 5 Hence  2 m 1 + 3 n 1 + m 1 n 1 = 57

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