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JEE Advanced Mathematics Area Under Curves 2023 JEE Advanced 2023 (Paper 1)

JEE Advanced Mathematics Question (2023) — Solution

Question

Let n ≥ 2  be a natural number and f : 0 ,   1 → ℝ be the function defined by f x = n 1 - 2 n x if 0 ≤ x ≤ 1 2 n 2 n 2 n x - 1 if 1 2 n ≤ x ≤ 3 4 n 4 n 1 - n x if 3 4 n ≤ x ≤ 1 n n n - 1 n x - 1 if 1 n ≤ x ≤ 1 If n is such that the area of the region bounded by the curves x = 0 ,   x = 1 ,   y = 0  and y = f x is 4 , then the maximum value of the function f is

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given, f x = n 1 - 2 n x , 0 ≤ x < 1 2 n 2 n 2 n x - 1 , 1 2 n ≤ x < 3 4 n 4 n 1 - n x , 3 4 n ≤ x ≤ 1 n n n - 1 n x - 1 , 1 n ≤ x ≤ 1 Here,  x ∈ 0 ,   1 Now  f x = n - 2 n 2 x  is decreasing in  0 ,   1 2 n   And  f x = 4 n 2 x - 4 n  increasing in  1 2 n ,   3 4 n And f x = 4 n - 4 n 2 x  decreasing in  3 4 n ,   1 n And f x = n 2 x - n n - 1  increasing in  1 n ,   1 Now plotting the graph of above function we get, Also,  f x ∈ 0 ,   n Now from above diagram area will be, A = 1 4 + 1 8 + 1 8 + n - 1 2 = 4   as   n ≥ 2 ⇒ 1 2 + n - 1 2 = 4 ⇒ n 2 = 4 ⇒ n = 8 So,  f x m a x = n = 8

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