Question
Let S= \ (x, y) R R : x 0, y 0, y^2 4 x, y^2 12-2 x . and .3 y+ 8 x 5 8 \ . If the area of the region S is 2 , then is equal to
JEE Advanced
Mathematics
Area Under Curves
2024
JEE Advanced 2024 (Paper 2)
JEE Advanced Mathematics Question (2024) — Solution
Options
- A. 17 2
- B. 17 3
- C. 17 4
- D. 17 5
Answer
B. 17 3
Step-by-step solution
Point of intersection of all curves is (2,2 2 ) Area = A _1+ A _2 2 = _0^2 2 x dx + 1 2 3 2 2 aligned & 2 =2 [ x^ 3 2 3 2 ]_0^2+3 2 \\ & 2 = 17 2 3 \\ & = 17 3 aligned
Related: Mathematics — Area Under Curves · All PYQ Banks