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JEE Advanced Mathematics Basic of Mathematics 2022 JEE Advanced 2022 (Paper 2)

JEE Advanced Mathematics Question (2022) — Solution

Question

The product of all positive real values of x satisfying the equation x 16 log 5 x 3 - 68 log 5 x = 5 - 16 is

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Taking log to the base 5  on both sides 16 log 5 x 3 - 68 log 5 x log 5 x = - 16 Let log 5 x = t 16 t 4 - 68 t 2 + 16 = 0 ⇒ 4 t 4 - 16 t 2 - t 2 + 4 = 0 ⇒ 4 t 2 - 1 t 2 - 4 = 0 ⇒ t = ± 1 2 , ± 2 So log 5 x = ± 1 2 or  ± 2 ⇒ x = 5 1 2 ,   5 - 1 2 ,   5 2 ,   5 - 2 Hence, the product is  5 × 1 5 × 25 × 1 25 = 1

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