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JEE Advanced Mathematics Continuity and Differentiability 2020 JEE Advanced 2020 (Paper 2)

JEE Advanced Mathematics Question (2020) — Solution

Question

Let the functions f : - 1 , 1 → ℝ  and  g : - 1 , 1 → - 1 , 1 be defined by  f x =   2 x - 1 + 2 x + 1   &   g x = x - x , where x denotes the greatest integer less than or equal to   x . Let f ∘ g : - 1 , 1 → ℝ  be the composite function defined by  f ∘ g x = f g x . Suppose c  is the number of points in the interval  - 1 , 1  at which  f ∘ g  is not continuous, and suppose d  is the number of points in the interval  - 1 ,   1  at which  f ∘ g  is not   differentiable. Then the value of  c + d is _____________

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

f x = 2 x - 1 + 2 x + 1 = - 4 x , x - 1 2 2 , - 1 2 ≤ x ≤ 1 2 4 x , x > 1 2 g x = x f g x = - 4 g x , g x - 1 2 2 , - 1 2 ≤ g x ≤ 1 2 4 g x g x > 1 2 Graph of g x is f g x = 2 , x ∈ - 1 , - 1 2 ∪ 0 , 1 2 4 x + 1 x ∈ - 1 2 , 0 4 x x ∈ 1 2 , 1 c = 1 at x = 0 d = 3 at x = - 1 2 , 0 , 1 2 , ∴ c + d = 4 .

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