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JEE Advanced Mathematics Definite Integration 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Mathematics Question (2021) — Solution

Question

For any real number  x , let  x  denotes the largest integer less than or equal to  x . If  I = ∫ 0 10 10 x x + 1 d x , then the value of  9 I  is ____.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given I = ∫ 0 10 10 x x + 1 d x Check the values of  x  at which the greatest integer function becomes integer. 10 x x + 1 = 1    ⇒    x = 1 9 10 x x + 1 = 4    ⇒    x = 2 3 10 x x + 1 = 9    ⇒    x = 9 I = ∫ 0 1 9 0 d x + ∫ 1 9 2 3 1 d x + ∫ 2 3 9 2 d x + ∫ 9 10 3 d x I = 0 + [ x ] 1 9 2 3 + [ 2 x ] 2 3 9 + [ 3 x ] 9 10 I = 2 3 - 1 9 + 18 - 4 3 + 30 - 27 I = 21 - 2 3 - 1 9 = 182 9 So,  9 I = 182

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Related: Mathematics — Definite Integration · All PYQ Banks