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JEE Advanced Mathematics Functions 2020 JEE Advanced 2020 (Paper 2)

JEE Advanced Mathematics Question (2020) — Solution

Question

Let the function  f : 0 , 1 → ℝ be defined by  f x = 4 x 4 x + 2 . Then the value of  f 1 40 + f 2 40 + f 3 40 + ⋯ + f 39 40 - f 1 2   is_________  

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

f x = 4 x 4 x + 2 ,    f 1 - x = 4 1 - x 4 1 - x + 2 = 2 4 x + 2 ⇒ f x + f 1 - x = 1 f 1 40 + f 2 40 + … . . + f 39 40 - f 1 2 = f 1 40 + f 39 40 + f 2 40 + f 38 40 + . . . . . f 19 40 + f 21 40 + f 20 40 - f 1 2 = 19 .

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