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JEE Advanced Mathematics Limits 2019 JEE Advanced 2019 (Paper 2)

JEE Advanced Mathematics Question (2019) — Solution

Question

Let F : R → R be a function. We say that f has:   PROPERTY 1   if lim h → 0 ⁡ f h - f 0 h exists and is finite, and  PROPERTY 2   if lim h → 0 ⁡ f h - f 0 h 2 exists and is finite. Then which of the following options is/are correct?

Options

  1. A. f x = x x has PROPERTY 2
  2. B. f x = x 2 / 3 has PROPERTY 1
  3. C. f x = sin ⁡ x has PROPERTY 2
  4. D. f x = x has PROPERTY 1

Answer

D. f x = x has PROPERTY 1

Step-by-step solution

A f x = x lim h → 0 ⁡ h - 0 h = lim h → 0 ⁡ h = 0 B f x = x 2 3 lim h → 0 ⁡ h 2 3 - 0 h = lim h → 0 ⁡ h 1 6 = 0 C f x = x x lim h → 0 ⁡ h h - 0 h 2 = lim h → 0 ⁡ h h = 1 , i f h → 0 + - 1 , i f h → 0 - Does not exist D f x = sin ⁡ x lim h → 0 ⁡ sin ⁡ h - 0 h 2 = lim h → 0 ⁡ 1 h sin ⁡ h h ⇒ does not exist

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