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JEE Advanced Mathematics Limits 2024 JEE Advanced 2024 (Paper 2)

JEE Advanced Mathematics Question (2024) — Solution

Question

Let the function f:[1, ) R be defined by f(t)= \ array cc (-1)^ n+1 2, & if t=2 n-1, n N , \\ (2 n+1-t) 2 f(2 n-1)+ (t-(2 n-1)) 2 f(2 n+1), & if 2 n-1 < t < 2 n+1, n N . array . Define g(x)= _1^x f(t) d t, x (1, ). Let denote the number of solutions of the equation g(x)=0 in the interval (1,8] and = _ x 1^+ g(x) x-1 . Then the value of + is equal to ________.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

f ( t )= \ array ccc 2 & ; & t =1 \\ 4-2 t & ; & 1

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