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JEE Advanced Mathematics Matrices 2021 JEE Advanced 2021 (Paper 1)

JEE Advanced Mathematics Question (2021) — Solution

Question

For any 3 × 3 matrix M , let | M | denote the determinant of M . Let E = 1 2 3 2 3 4 8 13 18 ,    P = 1 0 0 0 0 1 0 1 0   &   F = 1 3 2 8 18 13 2 4 3 If Q is a nonsingular matrix of order 3 × 3 , then which of the following statements is (are) TRUE ?

Options

  1. A. F = P E P and P 2 = 1 0 0 0 1 0 0 0 1
  2. B. E Q + P F Q - 1 = | E Q | + P F Q - 1
  3. C. ( E F ) 3 > | E F | 2
  4. D. Sum of the diagonal entries of P - 1 E P + F is equal to the sum of diagonal entries of E + P - 1 F P

Answer

D. Sum of the diagonal entries of P - 1 E P + F is equal to the sum of diagonal entries of E + P - 1 F P

Step-by-step solution

(1)  P 2 = 1 0 0 0 0 1 0 1 0 1 0 0 0 0 1 0 1 0 = 1 0 0 0 1 0 0 0 1 = I PEP = 1 0 0 0 0 1 0 1 0 1 2 3 2 3 4 8 13 18 1 0 0 0 0 1 0 1 0 = 1 2 3 8 13 18 2 3 4 1 0 0 0 0 1 0 1 0 = 1 3 2 8 18 13 2 4 3 = F (2) Here,  F = P E P ⇒ P F = P 2 E P ⇒ P F = E P ,  E = 0 ,   F = 0 E Q + P F Q - 1 = E Q + E P Q - 1 = ∣ E Q + P Q - 1 | = | E | | Q + P Q - 1 ∣ = 0 | E Q | + P F Q - 1 = 0 + 0 = 0 (3) Since,  | E | = 0 ⇒ | E F | = 0 Thus,  E F 3 > E F 2  is not possible (4) P = 1 0 0 0 0 1 0 1 0 ⇒ P = - 1 P - 1 =   A d j   P | P | = - - 1 0 0 0 0 - 1 0 - 1 0 = 1 0 0 0 0 1 0 1 0 P - 1 E P = 1 0 0 0 0 1 0 1 0 1 3 2 2 4 3 8 18 13 = 1 3 2 8 18 13 2 4 3 = F F + P - 1 E P = F + F = 2 F = 2 6 4 16 36 26 4 8 6 Sum of Diagonal elements of F + P - 1 E P = 44 E + P - 1 F P = E + 1 0 0 0 0 1 0 1 0 1 3 2 8 18 13 2 4 3 1 0 0 0 0 1 0 1 0 = 1 2 3 2 3 4 8 13 18 + 1 0 0 0 0 1 0 1 0 1 2 3 8 13 18 2 3 4 = 1 2 3 2 3 4 8 13 18 + 1 2 3 2 3 4 8 13 18 = 2 4 6 4 6 8 16 26 36 Tr E + P - 1 F P = 44

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