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JEE Advanced Mathematics Permutation Combination 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Mathematics Question (2021) — Solution

Question

Let  S 1 = i , j , k   : i , j , k ∈ 1 , 2 , … , 10 S 2 = i , j   : 1 ≤ i < j + 2 ≤ 10 , i , j ∈ 1 , 2 , … , 10 S 3 = i , j , k , l : 1 ≤ i < j < k < l , i , j , k , l ∈ 1 , 2 , ..... , 10 and   S 4 = i , j , k , l   :   i , j , k   and   l   are distint elements in   1 , 2 , . . . , 10 If the total number of elements in the set  S r  is  n r , r = 1 , 2 , 3 , 4  then which of the following statements is (are) TRUE?

Options

  1. A. n 1 = 1000
  2. B. n 2 = 44
  3. C. n 3 = 220
  4. D. n 4 12 = 420

Answer

D. n 4 12 = 420

Step-by-step solution

S i = i , j , k : i , j , k ∈ 1 , 2 , ... , 10 n 1 = 10 × 10 × 10 = 1000 i.e., number of elements in  S 1 = 1000 S 2 = i , j : 1 ≤ i < j + 2 ≤ 10 , i , j ∈ 1 , 2 , ... , 10 j i 1 1 , 2 2 1 , 2 , 3 ⋮   8 1 , 2 , 3 , . . . . , 9 n 2 = 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 44 S 3 = i , j , k , l : 1 ≤ i < j < k < l , i , j , k , l ∈ 1 , 2 , ....10 n 3 = 10 C 4 = 10 × 3 × 8 × 7 × 6 ! 4 × 3 × 2 × 1 × 6 ! = 210 i.e. number of elements in  S 3 = 210 S 4 = i , j , k , l : i , j , k   and   l   are distinct elements in   1 , 2 , ....... , 10 n 4 = 10 × 9 × 8 × 7  or  10 C 4 × 4 ! = 5040 n 4 12 = 5040 12 = 420

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