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JEE Advanced Mathematics Sequences and Series 2022 JEE Advanced 2022 (Paper 1)

JEE Advanced Mathematics Question (2022) — Solution

Question

Let l 1 , l 2 . . . l 100  be consecutive terms of an arithmetic progression with common difference d 1 , and let w 1 , w 2 , … , w 100  be consecutive terms of another arithmetic progression with common difference d 2 , where d 1 d 2 = 10 . For each  i = 1 , 2 , 3 . . . . . . . . . . 100 , let  R i  be a rectangle with length  l i , width  w i  and area  A i .If  A 51 - A 50 = 1000 , then the value of A 100 - A 90  is _______.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given  l 1 , l 2 . . . l 100  are consecutive terms of an  A . P Now let  T 1 = a  and common difference  = d 1   And similarly for A . P   w 1 , w 2 , . . . w 100 ,  T 1 = b  and common difference  = d 2 Now given,  A 51 - A 50 = l 51 w 51 - l 50 w 50 ⇒ a + 50 d 1 b + 50 d 2 - a + 49 d 1 b + 49 d 2 = 1000 ⇒ 50 b d 1 + 50 a d 2 + 2500 d 1 d 2 - 49 a d 2 - 49 b d 1 - 2401 d 1 d 2 = 1000 ⇒ b d 1 + a d 2 + 99 d 1 d 2 = 1000 So,  b d 1 + a d 2 = 10   as given  d 1 d 2 = 10 Now finding  A 100 - A 90 = l 100 w 100 - l 90 w 90  we get, = a + 99 d 1 b + 99 d 2 - a + 89 d 1 b + 89 d 2 = 99 b d 1 + 99 a d 2 + 99 2 d 1 d 2 - 89 b d 1 - 89 a d 2 - 89 2 d 1 d 2 = 10 b d 1 + a d 2 + 1880 d 1 d 2 = 10 10 + 18800   again using  d 1 d 2 = 10   &   b d 1 + a d 2 = 10 = 18900

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