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JEE Advanced Mathematics Trigonometric Equations 2024 JEE Advanced 2024 (Paper 1)

JEE Advanced Mathematics Question (2024) — Solution

Question

Let 2 < x < be such that x= -5 11 . Then ( 11 x 2 )( 6 x- 6 x)+ ( 11 x 2 )( 6 x+ 6 x) is equal to

Options

  1. A. 11 -1 2 3
  2. B. 11 +1 2 3
  3. C. 11 +1 3 2
  4. D. 11 -1 3 2

Answer

B. 11 +1 2 3

Step-by-step solution

Given, aligned & x=- 5 11 \\ & 1- ^2 x 2 2 x 2 =- 5 11 \\ & x 2 = 11 ,- 1 11 \\ & So, x 2 = 11 , As 4 < x 2 < 2 aligned aligned & As, x ( 2 , ) \\ & Now, ( 11 x 2 )( 6 x- 6 x)+ ( 11 x 2 )( 6 x+ 6 x) \\ & = \ 6 x 11 x 2 + 11 x 2 6 x \ \\ & = (6 x- 11 x 2 )+ (6 x- 11 x 2 ) \\ & = x 2 + x 2 \\ & = 1 2 3 + 11 2 3 \\ & = 11 +1 2 3 Option (2) is correct. aligned

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