Quantrex Academy · Free JEE Advanced PYQ solutions
JEE Advanced Physics Alternating Current 2025 JEE Advanced 2025 (Paper 1)

JEE Advanced Physics Question (2025) — Solution

Question

A circuit with an electrical load having impedance Z is connected with an AC source as shown in the diagram. The source voltage varies in time as V(t)=300 (400 t) V , where t is time in s. List-I shows various options for the load. The possible currents i(t) in the circuit as a function of time are given in List-II. Choose the option that describes the correct match between the entries in List-I to those in List-II. List-I List-II (P) (1) (Q) (2) (R) (3) (S) (4) (5)

Options

  1. A. P 3, Q 5, R 2, ~S 1
  2. B. P 1, Q 5, R 2, ~S 3
  3. C. P 3, Q 4, R 2, ~S 1
  4. D. P 1, Q 4, R 2, ~S 5

Answer

A. P 3, Q 5, R 2, ~S 1

Step-by-step solution

For P i= V R =10 400 t (3) For Q aligned & X_L= L=400 100 10^ -3 =40 \\ & Z=50 \\ & . i= 300 50 (400 t-53^ ) [current will lag by ^ -1 X_L R ] (5) aligned For R aligned & X _ C = 10^6 400 50 =50 and X _ L =400 25 10^ -3 =10 \\ & Z =50 \\ & i = 300 50 (400 t +53^ ) [ Current will lead by ^ -1 X _ C - X _ L R ] (2) aligned For S i = 300 60 (400 t ) X _ L = X _ C Resonance (1)

Practice more on Quantrex App →

Related: Physics — Alternating Current · All PYQ Banks