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JEE Advanced Physics Capacitance 2021 JEE Advanced 2021 (Paper 1)

JEE Advanced Physics Question (2021) — Solution

Question

In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q_ 1 C . Then S is switched to position Q . After a long time, the charge on the capacitor is q_ 2 C . The magnitude of  q 1  is _______.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

When  S  is connected to P ,  In steady state, i = 2 − 1 2 + 1 ⇒ i = 1 3   A Now, Charge on capacitor, q = C V ⇒ q = 1 μF 4 3   V ⇒ q = 4 3 μC ⇒ q = 1.33   μC

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