Quantrex Academy · Free JEE Advanced PYQ solutions
JEE Advanced Physics Capacitance 2021 JEE Advanced 2021 (Paper 1)

JEE Advanced Physics Question (2021) — Solution

Question

In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q_ 1 C . Then S is switched to position Q . After a long time, the charge on the capacitor is q_ 2 C . The magnitude of  q 2  is _____.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

When  S  is connected to  Q , i = 2 1 + 2 i = 2 3   A Now, after distribution of potential, q 2 = C V = 1 μF 2 3   V q 2 = 2 3   μC q 2 = 0.67   μC

Practice more on Quantrex App →

Related: Physics — Capacitance · All PYQ Banks