Question
In the following circuit C 1 = 12   μF , C 2 = C 3 = 4   μF and C 4 = C 5 = 2   μF . The charge stored in C 3 is μC .
JEE Advanced
Physics
Capacitance
2022
JEE Advanced 2022 (Paper 1)
JEE Advanced Physics Question (2022) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
From circuit given, Capacitors C 2 ,   C 3 ,   C 4 and C 5 are in parallel connection with constant potential difference as 2   V . Now, charge stored in C 3 is Q 3 = 2 × 4   μC = 8   μC .
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