Quantrex Academy · Free JEE Advanced PYQ solutions
JEE Advanced Physics Current Electricity 2022 JEE Advanced 2022 (Paper 2)

JEE Advanced Physics Question (2022) — Solution

Question

Two resistances R 1 = X   Ω  and R 2 = 1   Ω  are connected to a wire A B of uniform resistivity, as shown in the figure. The radius of the wire varies linearly along its axis from 0 . 2   mm  at A to 1   mm  at B . A galvanometer G  connected to the center of the wire, 50   cm  from each end along its axis, shows zero deflection when A and B are connected to a battery. The value of X is _______.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Resistance of frustum shaped conductor shown is R = ρ I π a b For the shown conductor in the diagram. r = a + b 2 = 0 . 2 + 1 2 = 0 . 6   mm Thus, the resistance of left half is  P = ρ × 0 . 5 × 10 6 π × 0 . 2 × 0 . 6 And the resistance of right half is  Q = ρ × 0 . 5 × 10 6 π × 0 . 6 × 1 For Wheatstone to be balanced R 1 P = R 2 Q ⇒ X π × 0 . 2 × 0 . 6 ρ × 0 . 5 × 10 6 = 1 π × 0 . 6 × 1 ρ × 0 . 5 × 10 6 ⇒ X = 5

Practice more on Quantrex App →

Related: Physics — Current Electricity · All PYQ Banks