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JEE Advanced Physics Electromagnetic Waves 2024 JEE Advanced 2024 (Paper 2)

JEE Advanced Physics Question (2024) — Solution

Question

A metal target with atomic number Z=46 is bombarded with a high energy electron beam. The emission of X-rays from the target is analyzed. The ratio r of the wavelengths of the K_ -line and the cut-off is found to be r=2. If the same electron beam bombards another metal target with Z=41, the value of r will be

Options

  1. A. 2.53
  2. B. 1.27
  3. C. 2.24
  4. D. 1.58

Answer

A. 2.53

Step-by-step solution

\( aligned & 1 _ = 3 4 R(Z-1)^2 p \\ & _ cut = h c e V \\ & Ratio 1 (Z-1)^2 for same beam \\ & Z x = 40^2 45^2 \\ & x= 45^2 40^2 .2 2.53 aligned \)

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