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JEE Advanced Physics Laws of Motion 2025 JEE Advanced 2025 (Paper 1)

JEE Advanced Physics Question (2025) — Solution

Question

A person sitting inside an elevator performs a weighing experiment with an object of mass 50 kg . Suppose that the variation of the height y (in m ) of the elevator, from the ground, with time t (in s ) is given by y=8 [1+ ( 2 t T ) ], where T=40 ~s . Taking acceleration due to gravity, g=10 ~m / s ^2, the maximum variation of the object's weight (in N ) as observed in the experiment is _______ .

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

y=8+8 2 t T With respect to elevator, variation in weight will be aligned & W = m ( a )_ \\ & W = m 2 ^2 ~A aligned Here elevator is performing SHM aligned & W =2 ~m ( 2 ~T )^2 A N \\ & W =2 50 ( 2 40 )^2 8 ~N \\ & ~W =2 50 1 400 8 ~N \\ & ~W = 800 400 ~N =2 ~N aligned

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