A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass m and radius r and it is in a uniform vertical magnetic field B_0, as shown in the figure. Initially, it hangs vertically downwards, because

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A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass m and radius r and it is in a uniform vertical magnetic field B_0, as shown in the figure. Initially, it hangs vertically downwards, because of acceleration due to gravity g, on two conducting supports at P and Q . When a current I is passed through the loop, the loop turns about the line PQ by an angle given by

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Correct answer: A. = r I B_0 /( mg )

aligned & Let loop makes angle with vertical. \ & in equilibrium _ net =0 \ & _0= MB (90- )- mg . r =0 \ & I. r ^2 B _0 = mg r.sin \ & = rIB _0 mg \ & aligned

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