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JEE Advanced Physics Motion In Two Dimensions 2025 JEE Advanced 2025 (Paper 2)

JEE Advanced Physics Question (2025) — Solution

Question

A projectile of mass 200 g is launched in a viscous medium at an angle 60^ with the horizontal, with an initial velocity of 270 ~m / s . It experiences a viscous drag force F =-c v where the drag coefficient c=0.1 ~kg / s and v is the instantaneous velocity of the projectile. The projectile hits a vertical wall after 2 s . Taking e=2.7, the horizontal distance of the wall from the point of projection (in m ) is

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

F _ net = m ~d v dt mg + F = md v dt mg - C v = md v dt Horizontal direction - Cv _ x = mdv _ x dt aligned & - C m _0^t d t= _ v_ 0 x ^ v_x d v_x v_x \\ & - t 2 = n v_x v_ 0 x \\ & d x d t =v_x=v_ 0 x e^ -t / 2 \\ & _0^ S_x d x=v_ 0 x _0^t e^ -t / 2 d t \\ & S_x=2 v_ 0 x (1-e^ -t / 2 ) \\ & at t=2 aligned aligned & S _ x =2 270 60^ [1- 1 e ] \\ & S _ x =270 (1- 1 2.7 ) \\ & = 270 2.7 (1.7) \\ & =170 ~m \\ & ~S _ x =170 ~m aligned

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