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JEE Advanced Physics Thermodynamics 2023 JEE Advanced 2023 (Paper 1)

JEE Advanced Physics Question (2023) — Solution

Question

One mole of an ideal gas expands adiabatically from an initial state ( T A ,   V 0 ) to final state ( T f ,   5 V 0 ) . Another mole of the same gas expands isothermally from a different initial state ( T B ,   V 0 ) to the same final state ( T f ,   5 V 0 ) . The ratio of the specific heats at constant pressure and constant volume of this ideal gas is γ . What is the ratio T A T B ?

Options

  1. A. 5 γ - 1
  2. B. 5 1 - γ
  3. C. 5 γ
  4. D. 5 1 + γ

Answer

A. 5 γ - 1

Step-by-step solution

As we know for an Adiabatic process T V γ - 1 = Constant . ⇒ T A V 0 γ - 1 = T f 5 V 0 γ - 1                         . . . i For Isothermal process T B = T f                         . . . ii Dividing equation i  by equation ii , we get ⇒ T A T B = 5 γ - 1

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Related: Physics — Thermodynamics · All PYQ Banks