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JEE Advanced Physics Thermodynamics 2025 JEE Advanced 2025 (Paper 2)

JEE Advanced Physics Question (2025) — Solution

Question

The left and right compartments of a thermally isolated container of length L are separated by a thermally conducting, movable piston of area A. The left and right compartments are filled with 3 2 and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant k and natural length 2 L 5 . In thermodynamic equilibrium, the piston is at a distance L 2 from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is P= k L ~A , then the value of is

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Extension in spring aligned & x=0.5 ~L -0.4 ~L \\ & =0.1 ~L aligned FBD of piston aligned & kx + P _2 ~A = P _1 ~A \\ & P _2 ~A = P _1 ~A - kx aligned P_2=P_1- k L A(10) ....(i) aligned & P _1 ~V = n _1 RT \\ & P _2 ~V = n _2 RT \\ & P _1 P _2 = n _1 n _2 = 3 2 aligned P _1= 3 2 P _2 ....(ii) aligned & P_2= 3 2 P_2- k L 10 A \\ & P_2 2 = k L 10 A \\ & P_2= k L 5 A = k L A \\ & = 1 5 =0.2 aligned

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