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JEE Advanced Physics Units and Dimensions 2020 JEE Advanced 2020 (Paper 1)

JEE Advanced Physics Question (2020) — Solution

Question

Sometimes it is convenient to construct a system of units so that all quantities can be expressed in terms of only one physical quantity. In one such system, dimensions of different quantities are given in terms of a quantity  X as follows: position = X α ;   speed = X β ;  acceleration = X p ; linear   momentum = X q ;  force = X r . Then

Options

  1. A. α + p = 2 β
  2. B. p + q - r = β
  3. C. p - q + r = α
  4. D. p + q + r = β

Answer

B. p + q - r = β

Step-by-step solution

momentum Force = X p - r ⇒ m v m a = X p - r ⇒ v a = X p - r but given that  v a = X β - p So,   p - r = β - p ⇒ 2 p = β + r       . . . 1 s p e e d 2 a c c e l e r a t i o n = p o s i t i o n ⇒ X 2 β X p = X α ⇒ 2 β - p = α ⇒ p + α = 2 β       . . . 2 and  f o r c e l i n e a r   m o m e n t u m = a c c e l e r a t i o n s p e e d ⇒ X r X q = X p X β ⇒ r - q = p - β ⇒ p + q - r = β       . . . 3

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