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JEE Advanced Physics Units and Dimensions 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Physics Question (2021) — Solution

Question

A physical quantity  S →  is defined as  S → = E → × B → μ 0 . where  E →  is electric field,  B →  is magnetic field and  μ 0  is the permeability of free space. The dimensions of  S →  are the same as the dimensions of which of the following quantity/quantities?

Options

  1. A. Energy Charge × Current
  2. B. Force Length × Time
  3. C. Energy Volume
  4. D. Power Area

Answer

D. Power Area

Step-by-step solution

Dimension of  Force Length × Time = MLT - 2 LT = MT - 3 Dimensions of Power Area = Force × Velocity Area = MLT - 2 × LT - 1 L 2 = MT - 3 ,  Dimension of Electric field  E ,   E = MA - 1 LT - 3 Dimensions of Magnetic field  B ;   B = MA - 1 T - 2 Dimension of magnetic permeability  μ 0 ;   μ 0 = MA - 2 T - 2 L Therefore, dimensions of  S , S = E B μ 0 = MA - 1 LT - 3 MA - 1 T - 2 MA - 2 T - 2 L = MT - 3

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