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JEE Advanced Physics Waves and Sound 2023 JEE Advanced 2023 (Paper 2)

JEE Advanced Physics Question (2023) — Solution

Question

S 1  and  S 2  are two identical sound sources of frequency 656   Hz . The source  S 1  is located at O and S 2 moves anti-clockwise with a uniform speed  4 2   m   s - 1  on a circular path around O , as shown in the figure. There are three points  P ,   Q and R on this path such that P and R are diametrically opposite while Q is equidistant from them. A sound detector is placed at point P . The source S 1 can move along direction O P . [Given: The speed of sound in air is 324   m   s − 1 ] When only S 2 is emitting sound and it is at Q , the frequency of sound measured by the detector in Hz is _____.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given: Source frequency,  f 0 = 656   Hz . Velocity of sound = 324   m   s - 1 . Velocity component of the source moving away from detector along like  P Q , V s = 4 2 cos 45 o = 4   m   s - 1 . Therefore, apparent frequency,  f = v v + v s f 0 = 324 324 + 4 656 ⇒ f = 648   Hz

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