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JEE Advanced Physics Waves and Sound 2024 JEE Advanced 2024 (Paper 1)

JEE Advanced Physics Question (2024) — Solution

Question

A source (S) of sound has frequency 240 ~Hz . When the observer ( O ) and the source move towards each other at a speed v with respect to the ground (as shown in Case 1 in the figure), the observer measures the frequency of the sound to be 288 ~Hz . However, when the observer and the source move away from each other at the same speed v with respect to the ground (as shown in Case 2 in the figure), the observer measures the frequency of sound to be n ~Hz . The value of n is ______

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Frequency received by observer f_0= ( C V_0 C V_S ) f_ s , C is speed of sound Case-1: aligned & f _1= ( C + V C - V ) f _ s \\ & 288= ( C + V C - V ) 240 aligned Case-2: f_2= ( C-V C+V ) f_S n = ( C - V C + V ) 240 multiply the two equations, we get. aligned & (288)( n )=(240)(240) \\ & n =200 aligned

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