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JEE Main Chemistry Alcohols Phenols and Ethers 2026 JEE Main 2026 (22 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Given below are two statements: Statement I : Phenol on treatment with CHCl _ 3 /aq. KOH under refluxing condition, followed by acidification produces p-hydroxy benzaldehyde as the major product and o-hydroxy benzaldehyde as the minor product. Statement II : The mixture of p-hydroxybenzaldehyde and o hydroxybenzaldehyde can be easily separated through steam distillation. In the light of the above statements, choose the correct answer from the options given below

Options

  1. A. Statement I is true but Statement II is false
  2. B. Statement I is false but Statement II is true
  3. C. Both Statement I and Statement II are true
  4. D. Both Statement I and Statement II are false

Answer

B. Statement I is false but Statement II is true

Step-by-step solution

Statement I: The reaction of phenol with CHCl_3 and aqueous KOH is the Reimer-Tiemann reaction. In this reaction, the major product is o-hydroxybenzaldehyde (salicylaldehyde) due to the formation of a stable six-membered chelate ring via intramolecular hydrogen bonding. p-hydroxybenzaldehyde is formed as the minor product. Thus, Statement I is false. Statement II: o-hydroxybenzaldehyde (salicylaldehyde) has intramolecular hydrogen bonding, making it more volatile (steam volatile). p-hydroxybenzaldehyde has intermolecular hydrogen bonding, which leads to association between molecules and a higher boiling point, making it non-steam volatile. Therefore, the mixture can be easily separated by steam distillation. Thus, Statement II is true. Conclusion: Statement I is false but Statement II is true.

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