Question
A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3 g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-
JEE Main
Chemistry
Amines
2026
JEE Main 2026 (24 January Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 59.5 %
- B. 72.5 \%
- C. 97.5 \%
- D. 81.5 \%
Answer
D. 81.5 \%
Step-by-step solution
Molar mass of aniline (C_6H_5NH_2) = 93 g/mol. Moles of aniline = 9.3/93 = 0.1 mol. From the reaction, theoretical yield of acetanilide = 0.1 mol. Molar mass of acetanilide (C_6H_5NHCOCH_3) = 135 g/mol. Theoretical mass = 0.1 × 135 = 13.5 g. Percentage yield = (11/13.5) × 100 = 81.5%
Related: Chemistry — Amines · All PYQ Banks