JEE Main Chemistry Question (2026) — Solution

Step-by-step solution

Cyclohexylmethylamine reacts with benzoyl chloride under basic conditions to form amide [A]: cyclohexylmethyl benzoamide. LiAlH₄ reduces the amide carbonyl to CH₂, converting the N-benzoyl group to a benzyl group. The product [B] is a secondary amine formed by reduction: cyclohexylmethyl-benzylamine (C_6H_ 11 -CH_2-NH-CH_2-C_6H_5). This structure contains secondary amine (N-H) with two carbon substituents: cyclohexylmethyl and benzyl groups.