Question
An organic compound ( P ) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br _ 2 and KOH forms compound (R) having molecular formula C _ 6 H _ 7 ~N . Names of P, Q and R respectively are.
JEE Main
Chemistry
Amines
2026
JEE Main 2026 (21 January Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. Phenylethanoic acid, phenylethanamide, benzamine
- B. Benzoic acid, 4-methylbenzamide, 4-methylaniline
- C. Toluic acid, methylbenzamide, 2-methylaniline
- D. Benzoic acid, benzamide, aniline
Answer
D. Benzoic acid, benzamide, aniline
Step-by-step solution
Q + Br_2/KOH → R is Hofmann bromamide degradation: Amide → Amine (with one less carbon). R = C_6H_7N = C_6H_5NH_2 = Aniline For Q to give aniline, Q = Benzamide (C_6H_5CONH_2) C_6H_5CONH_2 Br_2/KOH C_6H_5NH_2 P + hot NH_3 → Q: Carboxylic acid + NH_3 → Amide P = Benzoic acid (C_6H_5COOH) C_6H_5COOH NH_3, C_6H_5CONH_2 P = Benzoic acid, Q = Benzamide, R = Aniline
Related: Chemistry — Amines · All PYQ Banks