JEE Main
Chemistry
Biomolecules
2026
JEE Main 2026 (21 January Shift 2)
JEE Main Chemistry Question (2026) — Solution
Question
The correct statements are : A. Activation energy for enzyme catalysed hydrolysis of sucrose is lower than that of acid catalysed hydrolysis. B. During denaturation, secondary and tertiary structures of a protein are destroyed but primary structure remains intact. C. Nucleotides are joined together by glycosidic linkage between C _ 1 and C _ 4 carbons of the pentose sugar. D. Quaternary structure of proteins represents overall folding of the polypeptide chain. Choose the correct answer from the options given below :
Options
- A. A and B Only
- B. A, B and D Only
- C. B and C Only
- D. A, C and D Only
Step-by-step solution
Statement A is correct: Enzymes lower the activation energy barrier for reactions, making enzyme-catalyzed hydrolysis of sucrose have lower activation energy than acid-catalyzed hydrolysis. Statement B is correct: Denaturation disrupts hydrogen bonds and hydrophobic interactions maintaining secondary and tertiary structures, but the covalent peptide bonds forming the primary structure remain intact. Statement C is incorrect: Nucleotides are joined by phosphodiester linkages between the 3' and 5' carbons of adjacent sugar molecules, not between C1 and C4. Glycosidic linkages connect the nitrogenous base to the C1 carbon of the sugar. Statement D is incorrect: Quaternary structure describes the arrangement of multiple polypeptide subunits; tertiary structure represents the overall folding of a single polypeptide chain. Therefore only A and B are correct
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