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JEE Main Chemistry Chemical Bonding and Molecular Structure 2026 JEE Main 2026 (04 April Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

According to Lewis theory, the total number of bond-pairs and lone pair of electrons around the central atom of XeO_6^ 4- ion is _____.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

The central atom in XeO_6^ 4- is Xenon (Xe). The number of valence electrons in Xe is 8. Let the oxidation state of Xe in XeO_6^ 4- be x. x + 6(-2) = -4 x = +8 Since the oxidation state of Xe is +8, all 8 of its valence electrons are involved in bonding with the 6 oxygen atoms. There are no non-bonding electrons left on the central atom. Number of lone pairs on Xe = 0 Xe forms 6 bonds with the 6 oxygen atoms (and 2 bonds to satisfy its +8 oxidation state and minimize formal charge). Number of bond-pairs = 6 Total number of bond-pairs and lone pairs around the central atom = 6 + 0 = 6. Answer: 6

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