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JEE Main Chemistry Chemical Bonding and Molecular Structure 2026 JEE Main 2026 (24 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Among the following, the CORRECT combinations are A. IF _ 3 ~T -shaped (sp . ^ 3 ~d ) B. IF _ 5 Square pyramidal ( sp ^ 3 ~d ^ 2 ) C. IF _ 7 Pentagonal bipyramidal ( sp ^ 3 ~d ^ 3 ) D. ClO _ 4 ^ - Square planar ( sp ^ 2 ~d ) Choose the correct answer from the options given below:

Options

  1. A. B, C and D Only
  2. B. A and B Only
  3. C. A, B and C Only
  4. D. A, B, C and D

Answer

C. A, B and C Only

Step-by-step solution

Analyzing geometry and hybridization: A. IF₃: Iodine has 7 valence electrons, forms 3 bonds with F, leaving 2 lone pairs. Total electron pairs = 5 (trigonal bipyramidal geometry). Molecular shape is T-shaped. Hybridization = sp³d. CORRECT. B. IF₅: Iodine forms 5 bonds with F and has 1 lone pair. Total electron pairs = 6 (octahedral geometry). Molecular shape is square pyramidal with 1 lone pair in axial position. Hybridization = sp³d². CORRECT. C. IF₇: Iodine forms 7 bonds with F and has 0 lone pairs. Total electron pairs = 7. Molecular shape is pentagonal bipyramidal. Hybridization = sp³d³. CORRECT. D. ClO₄⁻: Chlorine has 7 valence electrons + 1 from charge = 8. Bonded to 4 O atoms with 0 lone pairs. Total electron pairs = 4 (tetrahedral geometry). Molecular shape is tetrahedral, NOT square planar. Hybridization = sp³, NOT sp²d. INCORRECT. Correct combinations: A, B, and C.

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