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JEE Main Chemistry Chemical Equilibrium 2026 JEE Main 2026 (08 April Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

Solid carbon, CaO and CaCO_3 are mixed and allowed to attain equilibrium at T K. CaCO _3(s) CaO (s) + CO _2(g) K_ p_1 = 0.08 atm C (s) + CO _2(g) 2 CO (g) K_ p_2 = 2 atm The partial pressure of CO is ________ 10^ -1 atm

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

For the first equilibrium: CaCO _3(s) CaO (s) + CO _2(g) K_ p_1 = P_ CO _2 = 0.08 atm For the second equilibrium: C (s) + CO _2(g) 2 CO (g) K_ p_2 = (P_ CO )^2 P_ CO _2 = 2 atm Substituting the value of P_ CO _2 : (P_ CO )^2 0.08 = 2 (P_ CO )^2 = 0.16 P_ CO = 0.4 atm = 4 10^ -1 atm Answer: 4

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