For the reaction, N _ 2 O _ 4 2 NO _ 2 , graph is plotted as shown below. Identify correct statements. A. Standard free energy change for the reaction is -5.40 ~kJ ~mol ^ -1 . B. As G ^ in graph is positive, N _ 2 O _ 4 will not dissociate into NO _ 2 at all. C. Reverse reaction will go to completio

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For the reaction, N _ 2 O _ 4 2 NO _ 2 , graph is plotted as shown below. Identify correct statements. A. Standard free energy change for the reaction is -5.40 ~kJ ~mol ^ -1 . B. As G ^ in graph is positive, N _ 2 O _ 4 will not dissociate into NO _ 2 at all. C. Reverse reaction will go to completion. D. When 1 mole of N _ 2 O _ 4 changes into equilibrium mixture, value of G ^ =-0.84 ~kJ ~mol ^ -1 E. When 2 mole of NO _ 2 changes into equilibrium mixture, G ^ for equilibrium mixture is -6.24 ~kJ ~mol ^ -1 . Choose the correct answer from the options given below :

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Correct answer: A. D and E only

From the graph of G vs fraction of N_2O_4 dissociated: At x = 0 (pure N_2O_4): G = 0 At equilibrium (x 0.4): G = -0.84 kJ/mol (minimum) At x = 1 (complete dissociation): G = 5.40 kJ/mol Statement A: G° = 5.40 kJ/mol (positive), not -5.40 kJ/mol. False. Statement B: Even with positive G°, equilibrium is established with partial dissociation. False. Statement C: Reverse reaction reaches equilibrium, not completion. False. Statement D: G = G_ eq - G_ N_2O_4 = -0.84 - 0 = -0.84 kJ/mol. True. Statement E: G = G_ eq - G_ NO_2 = -0.84 - 5.40 = -6.24 kJ/mol. True.

JEE Main Chemistry Question (2026) — Solution

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