Question
Decomposition of a hydrocarbon follows the equation k = (5.5 10^ 11 \, s ^ -1 )\,e^ -28000\, K T . The activation energy of reaction is __________ kJ mol^ -1 . (Nearest Integer) Given : R = 8.3 J K^ -1 mol^ -1
JEE Main
Chemistry
Chemical Kinetics
2026
JEE Main 2026 (06 April Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
According to the Arrhenius equation, k = A e^ - E_a RT . The given equation is k = (5.5 10^ 11 s ^ -1 ) e^ - 28000 T . Comparing the exponent of e in both equations: E_a RT = 28000 T E_a = 28000 R Substituting the value of R = 8.3 J K ^ -1 mol ^ -1 : E_a = 28000 8.3 J mol ^ -1 E_a = 232400 J mol ^ -1 E_a = 232.4 kJ mol ^ -1 Rounding to the nearest integer, the activation energy is 232. Answer: 232
Related: Chemistry — Chemical Kinetics · All PYQ Banks