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JEE Main Chemistry Chemical Kinetics 2026 JEE Main 2026 (05 April Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

For a reaction A P at T K , the half life (t_ 1/2 ) is plotted as a function of initial concentration [A]_0 of A as given below. The value of x in the given figure is _______ s (Nearest integer)

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

From the given graph, the plot of half-life t_ 1/2 versus initial concentration [A]_0 is a straight line passing through the origin. This indicates that t_ 1/2 is directly proportional to [A]_0, which means t_ 1/2 [A]_0. Therefore, the ratio t_ 1/2 [A]_0 is constant. Using the coordinates from the graph, we get: 240 4 10^ -3 = x 1.5 10^ -3 Solving for x: x = 240 1.5 10^ -3 4 10^ -3 x = 60 1.5 = 90 The value of x is 90. Answer: 90

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