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JEE Main Chemistry Chemical Kinetics 2026 JEE Main 2026 (22 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

A product (First order reaction). Three sets of experiment were performed for a reaction under similar experimental conditions: Run 1 100 ~mL of 10 M solution of reactant A Run 2 200 ~mL of 10 M solution of reactant A Run 3 100 ~mL of 10 M solution of reactant A +100 ~mL of H _ 2 O added. The correct variation of rate of reaction is

Options

  1. A. Run 1< Run 2< Run 3
  2. B. Run 3< Run 1< Run 2
  3. C. Run 3< Run 1 = Run 2
  4. D. Run 1= Run 2= Run 3

Answer

C. Run 3< Run 1 = Run 2

Step-by-step solution

For a first-order reaction, rate = k[A], where rate is directly proportional to reactant concentration. Run 1: 100 mL of 10 M solution Concentration = 10 M Rate: r_1 = k 10 Run 2: 200 mL of 10 M solution Concentration remains 10 M (increasing volume doesn't change concentration) Rate: r_2 = k 10 Therefore r_1 = r_2 Run 3: 100 mL of 10 M solution + 100 mL of H₂O Total moles of A = 10 M × 0.1 L = 1 mol Total volume = 0.2 L New concentration = 1 mol / 0.2 L = 5 M Rate: r_3 = k 5 Therefore r_3 < r_1 = r_2

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